5/(3x)-2/x^2+3/(2x)=(19x^2-12)/6x^2

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Solution for 5/(3x)-2/x^2+3/(2x)=(19x^2-12)/6x^2 equation: 



5/(3x)-2/x^2+3/(2x)=(19x^2-12)/6x^2

We move all terms to the left:

5/(3x)-2/x^2+3/(2x)-((19x^2-12)/6x^2)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 6x^2)!=0

x!=0/1

x!=0

x∈R



We calculate fractions

We do not support expression: x^6

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